200 ft
80 ft
x
Coach J was drawing out the triangle field for the Javelin Throw. He knew that the distance between the starting point and the midpoint of the furthest line was 200 feet. He also knew that the distance between the two other points was 80 feet. Coach J wanted the distance between the starting point and the other two points to be equal. Using the Pythagorean Theorem, he figured out that 200^2 + 80^2 = 46400. He also found out the square root of 46400 is 215.4 feet rounded to the nearest tenth.
Track and Field
By Cody Kemp
40 ft
x
35 degrees
Johnny threw a javelin. Coach J told Johnny that he threw the javelin at a 35-degree angle. When the javelin reached its highest height, Coach J said that it traveled 40 feet horizontally. Using trigonometry, he deduced that tan35 x 40 = 28 feet rounded to the nearest whole number. Coach J told Johnny that, when the javelin reached its highest point in the sky, it was about 28 feet high.
5.5 ft
30 ft
13 ft
x
johnny stood 30 feet away from the Pole Vault pit. He saw that the bar was 13 feet high and knew that he was 5.5 feet tall. Using trigonometry again, Johnny concluded that tan^-1 (7.5/30) = 14 degrees rounded to the nearest whole number. Therefore, the angle of elevation between his line of sight and the 30 feet distance to the pit was around 14 degrees.
30 degrees
x
Johhny stood 12 feet away from the base of the High Jump pit. Coach J said to him that he was standing at a 30-degree angle from the top pole. Using trigonometry once more, Johhny found out that 12/cos30 = 14 feet rounded to the nearest whole number. Johnny deduced that, from where he was standing, he was nearly 14 feet away from the top pole.
The End
200 ft
80 ft
x
Coach J was drawing out the triangle field for the Javelin Throw. He knew that the distance between the starting point and the midpoint of the furthest line was 200 feet. He also knew that the distance between the two other points was 80 feet. Coach J wanted the distance between the starting point and the other two points to be equal. Using the Pythagorean Theorem, he figured out that 200^2 + 80^2 = 46400. He also found out the square root of 46400 is 215.4 feet rounded to the nearest tenth.
Track and Field
By Cody Kemp
40 ft
x
35 degrees
Johnny threw a javelin. Coach J told Johnny that he threw the javelin at a 35-degree angle. When the javelin reached its highest height, Coach J said that it traveled 40 feet horizontally. Using trigonometry, he deduced that tan35 x 40 = 28 feet rounded to the nearest whole number. Coach J told Johnny that, when the javelin reached its highest point in the sky, it was about 28 feet high.
5.5 ft
30 ft
13 ft
x
johnny stood 30 feet away from the Pole Vault pit. He saw that the bar was 13 feet high and knew that he was 5.5 feet tall. Using trigonometry again, Johnny concluded that tan^-1 (7.5/30) = 14 degrees rounded to the nearest whole number. Therefore, the angle of elevation between his line of sight and the 30 feet distance to the pit was around 14 degrees.
30 degrees
x
Johhny stood 12 feet away from the base of the High Jump pit. Coach J said to him that he was standing at a 30-degree angle from the top pole. Using trigonometry once more, Johhny found out that 12/cos30 = 14 feet rounded to the nearest whole number. Johnny deduced that, from where he was standing, he was nearly 14 feet away from the top pole.
The End
200 ft
80 ft
x
Coach J was drawing out the triangle field for the Javelin Throw. He knew that the distance between the starting point and the midpoint of the furthest line was 200 feet. He also knew that the distance between the two other points was 80 feet. Coach J wanted the distance between the starting point and the other two points to be equal. Using the Pythagorean Theorem, he figured out that 200^2 + 80^2 = 46400. He also found out the square root of 46400 is 215.4 feet rounded to the nearest tenth.
Track and Field
By Cody Kemp
40 ft
x
35 degrees
Johnny threw a javelin. Coach J told Johnny that he threw the javelin at a 35-degree angle. When the javelin reached its highest height, Coach J said that it traveled 40 feet horizontally. Using trigonometry, he deduced that tan35 x 40 = 28 feet rounded to the nearest whole number. Coach J told Johnny that, when the javelin reached its highest point in the sky, it was about 28 feet high.
5.5 ft
30 ft
13 ft
x
johnny stood 30 feet away from the Pole Vault pit. He saw that the bar was 13 feet high and knew that he was 5.5 feet tall. Using trigonometry again, Johnny concluded that tan^-1 (7.5/30) = 14 degrees rounded to the nearest whole number. Therefore, the angle of elevation between his line of sight and the 30 feet distance to the pit was around 14 degrees.
30 degrees
x
Johhny stood 12 feet away from the base of the High Jump pit. Coach J said to him that he was standing at a 30-degree angle from the top pole. Using trigonometry once more, Johhny found out that 12/cos30 = 14 feet rounded to the nearest whole number. Johnny deduced that, from where he was standing, he was nearly 14 feet away from the top pole.
The End
200 ft
80 ft
x
Coach J was drawing out the triangle field for the Javelin Throw. He knew that the distance between the starting point and the midpoint of the furthest line was 200 feet. He also knew that the distance between the two other points was 80 feet. Coach J wanted the distance between the starting point and the other two points to be equal. Using the Pythagorean Theorem, he figured out that 200^2 + 80^2 = 46400. He also found out the square root of 46400 is 215.4 feet rounded to the nearest tenth.
Track and Field
By Cody Kemp
40 ft
x
35 degrees
Johnny threw a javelin. Coach J told Johnny that he threw the javelin at a 35-degree angle. When the javelin reached its highest height, Coach J said that it traveled 40 feet horizontally. Using trigonometry, he deduced that tan35 x 40 = 28 feet rounded to the nearest whole number. Coach J told Johnny that, when the javelin reached its highest point in the sky, it was about 28 feet high.
5.5 ft
30 ft
13 ft
x
johnny stood 30 feet away from the Pole Vault pit. He saw that the bar was 13 feet high and knew that he was 5.5 feet tall. Using trigonometry again, Johnny concluded that tan^-1 (7.5/30) = 14 degrees rounded to the nearest whole number. Therefore, the angle of elevation between his line of sight and the 30 feet distance to the pit was around 14 degrees.
30 degrees
x
Johhny stood 12 feet away from the base of the High Jump pit. Coach J said to him that he was standing at a 30-degree angle from the top pole. Using trigonometry once more, Johhny found out that 12/cos30 = 14 feet rounded to the nearest whole number. Johnny deduced that, from where he was standing, he was nearly 14 feet away from the top pole.
The End
200 ft
80 ft
x
Coach J was drawing out the triangle field for the Javelin Throw. He knew that the distance between the starting point and the midpoint of the furthest line was 200 feet. He also knew that the distance between the two other points was 80 feet. Coach J wanted the distance between the starting point and the other two points to be equal. Using the Pythagorean Theorem, he figured out that 200^2 + 80^2 = 46400. He also found out the square root of 46400 is 215.4 feet rounded to the nearest tenth.
Track and Field
By Cody Kemp
40 ft
x
35 degrees
Johnny threw a javelin. Coach J told Johnny that he threw the javelin at a 35-degree angle. When the javelin reached its highest height, Coach J said that it traveled 40 feet horizontally. Using trigonometry, he deduced that tan35 x 40 = 28 feet rounded to the nearest whole number. Coach J told Johnny that, when the javelin reached its highest point in the sky, it was about 28 feet high.
5.5 ft
30 ft
13 ft
x
johnny stood 30 feet away from the Pole Vault pit. He saw that the bar was 13 feet high and knew that he was 5.5 feet tall. Using trigonometry again, Johnny concluded that tan^-1 (7.5/30) = 14 degrees rounded to the nearest whole number. Therefore, the angle of elevation between his line of sight and the 30 feet distance to the pit was around 14 degrees.
30 degrees
x
Johhny stood 12 feet away from the base of the High Jump pit. Coach J said to him that he was standing at a 30-degree angle from the top pole. Using trigonometry once more, Johhny found out that 12/cos30 = 14 feet rounded to the nearest whole number. Johnny deduced that, from where he was standing, he was nearly 14 feet away from the top pole.
The End
200 ft
80 ft
x
Coach J was drawing out the triangle field for the Javelin Throw. He knew that the distance between the starting point and the midpoint of the furthest line was 200 feet. He also knew that the distance between the two other points was 80 feet. Coach J wanted the distance between the starting point and the other two points to be equal. Using the Pythagorean Theorem, he figured out that 200^2 + 80^2 = 46400. He also found out the square root of 46400 is 215.4 feet rounded to the nearest tenth.
Track and Field
By Cody Kemp
40 ft
x
35 degrees
Johnny threw a javelin. Coach J told Johnny that he threw the javelin at a 35-degree angle. When the javelin reached its highest height, Coach J said that it traveled 40 feet horizontally. Using trigonometry, he deduced that tan35 x 40 = 28 feet rounded to the nearest whole number. Coach J told Johnny that, when the javelin reached its highest point in the sky, it was about 28 feet high.
5.5 ft
30 ft
13 ft
x
johnny stood 30 feet away from the Pole Vault pit. He saw that the bar was 13 feet high and knew that he was 5.5 feet tall. Using trigonometry again, Johnny concluded that tan^-1 (7.5/30) = 14 degrees rounded to the nearest whole number. Therefore, the angle of elevation between his line of sight and the 30 feet distance to the pit was around 14 degrees.
30 degrees
x
Johhny stood 12 feet away from the base of the High Jump pit. Coach J said to him that he was standing at a 30-degree angle from the top pole. Using trigonometry once more, Johhny found out that 12/cos30 = 14 feet rounded to the nearest whole number. Johnny deduced that, from where he was standing, he was nearly 14 feet away from the top pole.
The End
200 ft
80 ft
x
Coach J was drawing out the triangle field for the Javelin Throw. He knew that the distance between the starting point and the midpoint of the furthest line was 200 feet. He also knew that the distance between the two other points was 80 feet. Coach J wanted the distance between the starting point and the other two points to be equal. Using the Pythagorean Theorem, he figured out that 200^2 + 80^2 = 46400. He also found out the square root of 46400 is 215.4 feet rounded to the nearest tenth.
Track and Field
By Cody Kemp
40 ft
x
35 degrees
Johnny threw a javelin. Coach J told Johnny that he threw the javelin at a 35-degree angle. When the javelin reached its highest height, Coach J said that it traveled 40 feet horizontally. Using trigonometry, he deduced that tan35 x 40 = 28 feet rounded to the nearest whole number. Coach J told Johnny that, when the javelin reached its highest point in the sky, it was about 28 feet high.
5.5 ft
30 ft
13 ft
x
johnny stood 30 feet away from the Pole Vault pit. He saw that the bar was 13 feet high and knew that he was 5.5 feet tall. Using trigonometry again, Johnny concluded that tan^-1 (7.5/30) = 14 degrees rounded to the nearest whole number. Therefore, the angle of elevation between his line of sight and the 30 feet distance to the pit was around 14 degrees.
30 degrees
x
Johhny stood 12 feet away from the base of the High Jump pit. Coach J said to him that he was standing at a 30-degree angle from the top pole. Using trigonometry once more, Johhny found out that 12/cos30 = 14 feet rounded to the nearest whole number. Johnny deduced that, from where he was standing, he was nearly 14 feet away from the top pole.
The End