Charles Law
Snemalna Knjiga Besedilo
- VOLUME AND TEMPERATURE AT CONSTANT PRESSURE OF A GAS
- Charles law is an experimental gas law that describes how gases tend toexpand when heated. The law states that the volume of a given quantity of gas is directlyproportional to the kelvin temperature, at constant pressure. The Law simply means that asthe temperature increases the, the volume also increases. Any change in kelvin temperaturewould likewise change the volume of the gas.
- Ok, Very Good!
- VOLUME AND TEMPERATURE AT CONSTANT PRESSURE OF A GAS
- Who formulated Charles Law?
- Jacques Charles, a French physicistinvestigated the effect of change of temperature on the volume
- V α T at constant n(gas) and P (pressure) orV= k T or K= V/TIf you are going to consider the initial and final conditions, you will arrive at the followingequations.V1 = K and V2 = kT1 T2
- Ms. Vien please write on the board, What is the mathematical expression of Charls Law.
- Very Good Ms. Vien
- Here Ma'am
- Okay, very good class. Take note class, it is important that the TEMPERATURE must be converted to "Kelvin" before solving Charles Law problem. What is the formula of Kelvin?
- Do you get it class?
- V1/T1 = K and V2/T2 = KSo now class, Whereas, V1 is the initial volume and V2 is the final volumeT1 is the initial temperature and T2 is the final temperatureIf the volume –temperature ratios are the same in the initial and final conditions then,We can rewrite the equation as:V1/T1 = V2/T2
- Yes ma'am
- To convert C to K, the formula of it is K= C+273.15
- Ok, let's try this problem. analyze the sample problem and answer it.
- Given: V1= 1.75L T1=25.0C+273.15=298.15kT2=50.0C+273.15=323.15KV2?Required: V2?Equation: V1/T1=V2/T1 OR V2= (V1)(T2)/T1Solution: V2= (1.75L)(323.15K) 298.15KANSWER: V2=1.90L
- Kr gas occupies a volume of 1.75 L at 25.0 C. Determine the volume of thegas if the temperature is increased to 50.0 C. What are the given?
- Very good class, you really understand our topic for today. That's all for today's class. Thank you for participating. <3
- Thank you Ma'am
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