Didn't you pay attention to your maths teacher in 10th grade? Very bad!
Oh! no problem... we can use TRIGNOMETRY
C
A
B
So I know that my hair is 20 m long. and the angle of elevation here looks like 30degrees. So the question here is, how long must be the tower?
Hmmmso that means the tower is 10m long..
So, AB= LENGTH OF THE TOWER AC=LENGTH OF MY HAIRANGLE C= ANGLE OF ELEVATION =30 DEGREES.
SIN 30= OPP/ HYP1/2=AB/ACAB=20/2=10m
C
how much do you think will be the angle of depression in this case?
TAN 6O=OPP/ADJ√3=A/BC√=10/BCBC=10√3
Now we have to apply the same logic with the same measurements we found earlier to see how much distance will be there between you and the foot of the tower when you are down..
AB= length of the tower=10mangle A=ANGLE OF DEPRESSION =60 DEGREESBC= DISTANCE BETWEEN YOU AND THE FOOT OF THE TOWER
A
B
about 60 DEGREES
OKAY I WILL....BYEE
SEE! MY CALCULATIONS WERE ON POINT!THANKS TO MY 10TH GRADE MATHS TEACHER... NEXT TIME WHEN YOU COME, LEARN SOME TRIGNOMETRY AND COME. IF POSSIBLE LEARN IT FROM MY 10TH GRADE MATHS TEACHER. SHE TEACHES THE BEST..BYEEE!!
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