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Siužetinės Linijos Tekstas
- Let me explain this to you in a better way.
- Sure okay, so for this problem, you have to do a proportion.
- The drawing of a building shown below has a scale of 1in=20ft, if their is 2in and 3in in both sides, what is the actual area of the building
- Hey sis can you help me with this math problem?
- 1inch= 20ft
- Okay so this is our first proportion, that were doing to see how much feet are 3 inches here.
- 20 x
- ______1______=______3____
- Okay first lets set up our language. in other words, how were going to set up the proportion. so lets do inches over feet.
- Lets cross multiply 20 x 3 = 60 and then divide it by 1 and you get 60ft
- 3in
-
- 2in
- So in this case, the actual length would be 3 in = 60ft. Now lets move on to the other proportion!
- in/ft
- Okay so this is our second proportion, that were doing to see how much feet are 2 inches here.
- 1inch= 20ft
- 20 x
- ______1______=______2____
- Language: in/ft
- Lets cross multiply 20 x 2 = 40 and then divide it by 1 and you get 40ft
- 3in
-
- 2in
- So in this case, the actual width would be 2 in = 40ft. Were not done yet!
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