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QUADRATIC

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Create your own at Storyboard That

f(x)=-x^2-2x+3 is theequation I want to graph.

Ok first we need to find the axis ofsymmetry.

It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.

Ok so now how do we find the vertex?

Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so justsubstitute!

Lets walk on the way because we have to get home.

I found my y-value!

Ok now take your x value from axis of symmetry and put it together with the y value to make acoordinatethat's your vertex!

Oh wow that was easy

But were not done yet we need to find the y-intercept.

I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?

Yeah that's right, you canactually listen!

I was just playing with you.

Hey that's not funny!

Now you find the x-intercept by plugging y in as 0

I got it and I plotted on the y-intercepton both sides equallyseparatefrom each other.

Just like the y-intercept but with y as 0.

Yup just the same thing but there is a trick you can use vietas method

Oh yea Ms.Beard taught me that

There's nothing like being at home.

I found everything and plotted it what do I do now?

Now you need to draw it through all the points to make a U shape.

I drew a line since the graph is facing downwards would it be a maximum?

Correct you just graphed your first quadratic formula!

Create your own at Storyboard That

f(x)=-x^2-2x+3 is theequation I want to graph.

Ok first we need to find the axis ofsymmetry.

It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.

Ok so now how do we find the vertex?

Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so justsubstitute!

Lets walk on the way because we have to get home.

I found my y-value!

Ok now take your x value from axis of symmetry and put it together with the y value to make acoordinatethat's your vertex!

Oh wow that was easy

But were not done yet we need to find the y-intercept.

I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?

Yeah that's right, you canactually listen!

I was just playing with you.

Hey that's not funny!

Now you find the x-intercept by plugging y in as 0

I got it and I plotted on the y-intercepton both sides equallyseparatefrom each other.

Just like the y-intercept but with y as 0.

Yup just the same thing but there is a trick you can use vietas method

Oh yea Ms.Beard taught me that

There's nothing like being at home.

I found everything and plotted it what do I do now?

Now you need to draw it through all the points to make a U shape.

I drew a line since the graph is facing downwards would it be a maximum?

Correct you just graphed your first quadratic formula!

Create your own at Storyboard That

f(x)=-x^2-2x+3 is theequation I want to graph.

Ok first we need to find the axis ofsymmetry.

It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.

Ok so now how do we find the vertex?

Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so justsubstitute!

Lets walk on the way because we have to get home.

I found my y-value!

Ok now take your x value from axis of symmetry and put it together with the y value to make acoordinatethat's your vertex!

Oh wow that was easy

But were not done yet we need to find the y-intercept.

I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?

Yeah that's right, you canactually listen!

I was just playing with you.

Hey that's not funny!

Now you find the x-intercept by plugging y in as 0

I got it and I plotted on the y-intercepton both sides equallyseparatefrom each other.

Just like the y-intercept but with y as 0.

Yup just the same thing but there is a trick you can use vietas method

Oh yea Ms.Beard taught me that

There's nothing like being at home.

I found everything and plotted it what do I do now?

Now you need to draw it through all the points to make a U shape.

I drew a line since the graph is facing downwards would it be a maximum?

Correct you just graphed your first quadratic formula!

Create your own at Storyboard That

f(x)=-x^2-2x+3 is theequation I want to graph.

Ok first we need to find the axis ofsymmetry.

It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.

Ok so now how do we find the vertex?

Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so justsubstitute!

Lets walk on the way because we have to get home.

I found my y-value!

Ok now take your x value from axis of symmetry and put it together with the y value to make acoordinatethat's your vertex!

Oh wow that was easy

But were not done yet we need to find the y-intercept.

I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?

Yeah that's right, you canactually listen!

I was just playing with you.

Hey that's not funny!

Now you find the x-intercept by plugging y in as 0

I got it and I plotted on the y-intercepton both sides equallyseparatefrom each other.

Just like the y-intercept but with y as 0.

Yup just the same thing but there is a trick you can use vietas method

Oh yea Ms.Beard taught me that

There's nothing like being at home.

I found everything and plotted it what do I do now?

Now you need to draw it through all the points to make a U shape.

I drew a line since the graph is facing downwards would it be a maximum?

Correct you just graphed your first quadratic formula!

Create your own at Storyboard That

f(x)=-x^2-2x+3 is theequation I want to graph.

Ok first we need to find the axis ofsymmetry.

It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.

Ok so now how do we find the vertex?

Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so justsubstitute!

Lets walk on the way because we have to get home.

I found my y-value!

Ok now take your x value from axis of symmetry and put it together with the y value to make acoordinatethat's your vertex!

Oh wow that was easy

But were not done yet we need to find the y-intercept.

I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?

Yeah that's right, you canactually listen!

I was just playing with you.

Hey that's not funny!

Now you find the x-intercept by plugging y in as 0

I got it and I plotted on the y-intercepton both sides equallyseparatefrom each other.

Just like the y-intercept but with y as 0.

Yup just the same thing but there is a trick you can use vietas method

Oh yea Ms.Beard taught me that

There's nothing like being at home.

I found everything and plotted it what do I do now?

Now you need to draw it through all the points to make a U shape.

I drew a line since the graph is facing downwards would it be a maximum?

Correct you just graphed your first quadratic formula!

Create your own at Storyboard That

f(x)=-x^2-2x+3 is theequation I want to graph.

Ok first we need to find the axis ofsymmetry.

It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.

Ok so now how do we find the vertex?

Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so justsubstitute!

Lets walk on the way because we have to get home.

I found my y-value!

Ok now take your x value from axis of symmetry and put it together with the y value to make acoordinatethat's your vertex!

Oh wow that was easy

But were not done yet we need to find the y-intercept.

I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?

Yeah that's right, you canactually listen!

I was just playing with you.

Hey that's not funny!

Now you find the x-intercept by plugging y in as 0

I got it and I plotted on the y-intercepton both sides equallyseparatefrom each other.

Just like the y-intercept but with y as 0.

Yup just the same thing but there is a trick you can use vietas method

Oh yea Ms.Beard taught me that

There's nothing like being at home.

I found everything and plotted it what do I do now?

Now you need to draw it through all the points to make a U shape.

I drew a line since the graph is facing downwards would it be a maximum?

Correct you just graphed your first quadratic formula!

Create your own at Storyboard That

f(x)=-x^2-2x+3 is theequation I want to graph.

Ok first we need to find the axis ofsymmetry.

It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.

Ok so now how do we find the vertex?

Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so justsubstitute!

Lets walk on the way because we have to get home.

I found my y-value!

Ok now take your x value from axis of symmetry and put it together with the y value to make acoordinatethat's your vertex!

Oh wow that was easy

But were not done yet we need to find the y-intercept.

I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?

Yeah that's right, you canactually listen!

I was just playing with you.

Hey that's not funny!

Now you find the x-intercept by plugging y in as 0

I got it and I plotted on the y-intercepton both sides equallyseparatefrom each other.

Just like the y-intercept but with y as 0.

Yup just the same thing but there is a trick you can use vietas method

Oh yea Ms.Beard taught me that

There's nothing like being at home.

I found everything and plotted it what do I do now?

Now you need to draw it through all the points to make a U shape.

I drew a line since the graph is facing downwards would it be a maximum?

Correct you just graphed your first quadratic formula!

Create your own at Storyboard That

f(x)=-x^2-2x+3 is theequation I want to graph.

Ok first we need to find the axis ofsymmetry.

It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.

Ok so now how do we find the vertex?

Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so justsubstitute!

Lets walk on the way because we have to get home.

I found my y-value!

Ok now take your x value from axis of symmetry and put it together with the y value to make acoordinatethat's your vertex!

Oh wow that was easy

But were not done yet we need to find the y-intercept.

I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?

Yeah that's right, you canactually listen!

I was just playing with you.

Hey that's not funny!

Now you find the x-intercept by plugging y in as 0

I got it and I plotted on the y-intercepton both sides equallyseparatefrom each other.

Just like the y-intercept but with y as 0.

Yup just the same thing but there is a trick you can use vietas method

Oh yea Ms.Beard taught me that

There's nothing like being at home.

I found everything and plotted it what do I do now?

Now you need to draw it through all the points to make a U shape.

I drew a line since the graph is facing downwards would it be a maximum?

Correct you just graphed your first quadratic formula!

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Siužetinės Linijos Tekstas

  • There's nothing like being at home.
  • Now you need to draw it through all the points to make a U shape.
  • Correct you just graphed your first quadratic formula!
  • I drew a line since the graph is facing downwards would it be a maximum?
  • I found everything and plotted it what do I do now?
  •  It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.
  • Ok first we need to find the axis of symmetry.
  • f(x)=-x^2-2x+3 is the equation I want to graph.
  • Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so just substitute!
  • Lets walk on the way because we have to get home.
  • Ok so now how do we find the vertex?
  • Ok now take your x value from axis of symmetry and put it together with the y value to make a coordinate that's your vertex!
  • But were not done yet we need to find the y-intercept.
  • Oh wow that was easy
  • I found my y-value!
  • Yup just the same thing but there is a trick you can use vietas method
  • Now you find the x-intercept by plugging y in as 0
  • Oh yea Ms.Beard taught me that
  • I got it and I plotted on the y-intercept on both sides equally separate from each other.
  • Just like the y-intercept but with y as 0.
  • I was just playing with you.
  • Yeah that's right, you can actually listen!
  • I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?
  • Hey that's not funny!
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