This is a story of Emma and her time selling Prom tickets
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Tickets For Prom
Hi! I'm Emma. I'm helping my friend in the dance committee sell Prom tickets.
Prom TicketsJuniors $$Seniors $
If on the first day of sales, we sold 10 Senior tickets and 15 Junior tickets for $100, and on the second day, we sold 8 Senior tickets and 10 Junior tickets for $70, how much money would each ticket be worth?
To solve this, we would first want to create our equations. If we make X the price of Senior tickets and Y the price of Junior tickets, our equation would look something like this:10X + 15Y = 100+ 8X + 10Y = 70
We then have to find the least common multiples of 10 and 8. In this case, the least common multiples are 10 and 8.
To be able to use the process of elimination, we would want to pick either the X or Y value to eliminate. I think we should eliminate Xvalue.
Now that we know we are getting rid of the X value, we need to multiply the equations by the LCM. The first equation would be multiplied by 8 and the second equation by -10. We multiply the second equation by a (-) so that the Xs will cancel out. We would then have:80X + 120Y = 800+ -80X - 100Y = -700 20Y = 100 20 20
After that, we solve the equations which would give us 20Y = 100. Then, we divide 20 on each side, canceling the 20 and giving us our solution; that the Junior tickets cost $5.
We would get rid of the 80X because a positive and negative cancel each other out.
Now that we know what Y is, we need to figure out what X is. To do this, we simply plug in the Y value into either original equation. So it could look something like this:8X + 10(5) = 70 8X + 50 = 70 -50 -50 8X = 20
After we add the Y value to the equation we're left with 8X + 50 = 70.We then need to subtract 50 from each side. The 50 cancels out. This leaves us with 8X = 20
We then divide each side by 8. This isolates the X from the 8 and gives us our solution, that the Senior tickets cost $2.50