Now you need to draw it through all the points to make a U shape.
Correct you just graphed your first quadratic formula!
I drew a line since the graph is facing downwards would it be a maximum?
I found everything and plotted it what do I do now?
It is a vertical line that passes through the vertex of a parabola the divides it into two congruent halves.
Ok first we need to find the axis of symmetry.
f(x)=-x^2-2x+3 is the equation I want to graph.
Remember how I told by finding the axis of sym. we would find the x value of the vertex now we need to plug in that x value into the equation so just substitute!
Lets walk on the way because we have to get home.
Ok so now how do we find the vertex?
Ok now take your x value from axis of symmetry and put it together with the y value to make a coordinate that's your vertex!
But were not done yet we need to find the y-intercept.
Oh wow that was easy
I found my y-value!
Yup just the same thing but there is a trick you can use vietas method
Now you find the x-intercept by plugging y in as 0
Oh yea Ms.Beard taught me that
I got it and I plotted on the y-intercept on both sides equally separate from each other.
Just like the y-intercept but with y as 0.
I was just playing with you.
Yeah that's right, you can actually listen!
I think I heard my teacher say to find the y-intercept we need to make x=0 is that right?