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  • Word problem: Marites is a fish vendor that opened up her own fish store. Marites stated that the profit P she earns for selling x number of fish products can be modelled as p(x) = x2 - 35x + 1200. She wondered how many fish she could sell to earn at most 950 pesos worth of profit?
  • Given: x2 – 35x + 1200 ≤ 950 x2 – 35x + 1200 – 950 < 0x2 – 35x + 250 = 0(x – 25) (x – 10) = 0x - 25 = 0 x - 10 = 0x = 25 x = 10
  • SOLUTIONS
  • SOLUTIONS
  • Testing points: x2 – 35x + 1200 ≤ 950x < 10 = 010 < x < 25 = 11x > 25 = 26
  • SOLUTIONS
  • x2 – 35x + 1200 ≤ 950; 11(11)2 – 35(11) + 1200 ≤ 950121 – 385 + 1200 ≤ 950936 ≤ 950 TRUE
  • x2 – 35x + 1200 ≤ 950; 0(0)2 – 35(0) + 1200 ≤ 9500 - 0 + 1200 ≤ 9501200 ≤ 950 FALSE
  • SOLUTIONS
  •  x2 – 35x + 1200 ≤ 950; 26(26)2 – 35(26) + 1200 ≤ 950 676 – 910 + 1200 ≤ 950 -234 + 1200 ≤ 950 966 ≤ 950 FALSE
  • Answer: The solution to the inequality x2 - 35x + 1200 ≤ 950 is [x | 10 ≤ x ≤ 25]. The number of fish products that must be bought with at most 950 pesos is greater than or equal to 10 but less or equal to 25. 
Над 30 милиона създадени разкадровки