Math Performance Task(Situation #1)
نص القصة المصورة
- Volleyball Return Pass!
- 50 Degrees
- 70°
- 70°
- Adj = 15
- 110 Degrees
- Opp = 20
- 180-110= 7070 is the reference angle.Quad: 2Reference: 70Function: SInSign: +
- 180
- 110
- T
- S
- 70
- 270
- 90
- A
- C
- 360
- The ball is being served at a 50 degree angle doing down.
- 180-110= 7070 = reference angle.Quad: 2Reference: 70Function: SInSign: +
- 110
- S
- S
- 90
- In Quadrant 2 the sin function is positive which makes the answer positive since looking for Sin
- The person needs to return the ball and he did at a 110 Degree angle.
- 180-110= 7070 is the reference angle.Quad: 2Reference: 70Function: CotSign: -
- 110
- S
- 90
- A
- Let's take out my favorite tool the notebook. First we find Sin.
- 180-110= 7070 = reference angle.Quad: 2Reference: 70Function: CotSign: -
- 110
- S
- S
- 90
- In Quadrant 2 the sin function is positive which makes the answer negative since we're looking for Cot.
- Let's explain the process of Sin.When we put everything together we get +Sin70Positive for the second quad. Sin for the function and 70 for the reference angle.
- 180
- T
- 70
- 270
- C
- 360
- We subtract the angle by 180 because it's in the 2nd quadrant. This gives us the reference angle.
- Let's take out my favorite tool the notebook. Now we find Cot.
- 180
- T
- 70
- 270
- C
- 360
- Let's explain the process of Cot.When we put everything together we get -Cot70Negative for the second quad. Cot for the function and 70 for the reference angle. Answers are +Sin70 and -Cot70.
- 180
- T
- 70
- 270
- C
- 360
- We subtract the angle by 180 because it's in the 2nd quadrant. This gives us the reference angle.
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